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\fancyhead[CE]{Massoud Mashreghi} 
\fancyhead[CO]{Convolution Integral Equations with Two Kernels}



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{\noindent Journal of Mathematical Extension \\

‎\vspace*{9mm}
‎
\begin{center}

{\Large \bf 
Convolution Integral Equations with Two Kernels\\}

\let\thefootnote\relax\footnote{\scriptsize Received: XXXX}

{\bf Massoud Mashreghi}\vspace*{-2mm}\\
\vspace{2mm} {\small Department of Applied Mathematics,  Hakim Sabzevari University} \vspace{2mm}

\end{center}

\vspace{4mm}


{\footnotesize
\begin{quotation}
{\noindent \bf Abstract.} In this paper, we consider the integral equation of convolution type with some conditions which has two kernels. At first we change this integral equation to a simple operator form and then, we approximate it by Topelitzian and Hankelian series.
\end{quotation}
\begin{quotation}
\noindent{\bf AMS Subject Classification:} 45A05

\noindent{\bf Keywords and Phrases:} Ambartsumian's equation, Yengibaryan's equation, Dual integral equation,
Canonical factorization, Toeplitz matrices , Hankel matrices
\end{quotation}}

\section{Introduction}
Integral equation on the half-line with a kernel that depends on the difference of the arguments  called Wiener-Hopf  Integral Equations. In this paper, we use the notation WHIE for this type of integral equations. This type of integral equations  have important and multiple applications in  different areas of mathematical natural sciences such as neutron transport theory, nuclear reactor, astrophysics and atmosphere optic  \cite{amb, bus, chan}.
A new factorization method recently found by Yengibaryan  \cite{aren}
leads in many cases to analytical or effective numerical solutions of the WHIE and  the integral equation of the convolution type where has the following form\\
\begin{eqnarray*}
f(x)=g(x)+\int\limits_{-\infty}^{\infty} k(x-t)f(t)dt.
\end{eqnarray*}
Ambartsumian's invariance principle led to a wide and useful application in the theory of WHIE of nonlinear functional equations, Ambartsumian's equations which is in the following form
\begin{eqnarray}
\varphi (s)=1+\varphi (s) \int\limits_{a}^{b} \frac{1}{s+p} \varphi (p) d\sigma (p),
\end{eqnarray}
 plays an important role in effective solution and the mathematical study of special classes of the nonsingular and singular WHIE  \cite{amb, chan}.


% % % % % % % % % % % % % % % %
This paper is devoted to investigation on the integral equation of the convolution type with two kernels on the entire line in the following form
\begin{eqnarray}\label{eq:equation}
f(x)=g(x)+\int\limits_{0}^{\infty}T_1(x-t)f(t)dt+\int\limits_{-\infty}^{0}T_2(x-t)f(t)dt,\quad x\in\mathbb{R}
\end{eqnarray}
where $f\in L^{loc} _1(-\infty,\infty)$ is the unknown function and we know a function is called locally integrable if, around every point in the domain, there is a neighborhood on which the function is integrableand ang $g,T_{1,2}$ are the functions that  have the following properties\\
\begin{eqnarray*}
g \in E,\quad 0 \leq T_j \in L_1 (-\infty,\infty),\quad \lambda_j \equiv \int\limits_{-\infty}^{\infty} T_j(x) dx \leq 1 \quad j=1,2.
\end{eqnarray*}
where $E$ is one of Banach spaces $L_p(-\infty,+\infty)\quad  for\quad  1 \leq p \leq \infty .$

\section{Operator form of the convolution equation}
In this section we will reduce the equation (\ref{eq:equation}) to the operator form and then, we will study on operator form which solvability of this operator form  is equvalent to solvabilty of (\ref{eq:equation}).
%Here will be introduced a new way for approximating the equation (\ref{eq:equation}).
% % % % % % % % % % % % % % % % % % % % % % % % % % % %
\par Here we present the two definition of the following functions
\begin{eqnarray} \label{sign}
f^{\pm} (x)=f(\pm x)\quad;\quad g^{\pm} (x)=g(\pm x).
\end{eqnarray}
 Considering the relations (\ref{sign}), the  equation (\ref{eq:equation}) can be rewritten as
\begin{eqnarray}\label{equation+}
f^+(x)=g^+(x)+\int\limits_{0}^{\infty}T_1(x-t)f^+(t)dt+\int\limits_{-\infty}^{0}T_2(x-t)f^-(-t)dt,\quad x>0.
\end{eqnarray}
In  (\ref{equation+}), we change $-t$ to $t$ and then the new form of equation(\ref{equation+}) will be as %(\ref{equation+})
%Takes the form:
\begin{eqnarray}\label{equation++}
f^+(x)=g^+(x)+\int\limits_{0}^{\infty}T_1(x-t)f^+(t)dt+\int\limits_{0}^{\infty}T_2(x+t)f^-(t)dt,\quad x>0.
\end{eqnarray}
Similarly, we can write
%\begin{scriptsize}
\begin{footnotesize}
\begin{eqnarray} \label{equation-}
f^-(-x)=g^-(-x)+\int\limits_{0}^{\infty}T_1(-x-t)f^+(t)dt+\int\limits_{-\infty}^{0}T_2(-x-t)f^-(-t)dt,\quad x<0
\end{eqnarray}
\end{footnotesize}
%\end{scriptsize}
Reformulation of (\ref{equation-}) can be considered as
\begin{footnotesize}
\begin{eqnarray}\label{equation--}
f^-(x)=g^-(x)+\int\limits_{0}^{\infty}T_1(-(x+t))f^+(t)dt+\int\limits_{0}^{\infty}T_2(-(x-t))f^-(t)dt,\quad x>0.
\end{eqnarray}
\end{footnotesize}
Now the relations (\ref{equation++}) and (\ref{equation--}) indicate that integral equation (\ref{eq:equation}) is equivalent to the system of integral equations of the form

\begin{footnotesize}
\begin{eqnarray}\label{sys1}
\begin{cases}
f^+(x)=g^+(x)+\int\limits_{0}^{\infty}T_1(x-t)f^+(t)dt+\int\limits_{0}^{\infty}T_2(x+t)f^-(t)dt,\phantom{aaaaaaaaa} x>0\\
%               &        &     \\
f^-(x)=g^-(x)+\int\limits_{0}^{\infty}T_1(-(x+t))f^+(t)dt+\int\limits_{0}^{\infty}T_2(-(x-t))f^-(t)dt,\quad\quad x>0.
\end{cases}
\end{eqnarray}
\end{footnotesize}

\noindent Now we define the following functions
\begin{eqnarray*}\label{new functions}
K_1(x)=T_1(x), \quad K^0_1(x)=T_2(x),\phantom{aaaa}x>0 \\ K^0_2(x)=T_1(-x), \quad K_2(x)=T_1(-x),\quad\quad x>0.
\end{eqnarray*}
By the last notation we can rewrite the system (\ref{sys1}) to the following form
\begin{eqnarray}\label{sys2}
\begin{cases}


f^+(x)=g^+(x)+\int\limits_{0}^{\infty}K_1(x-t)f^+(t)dt+\int\limits_{0}^{\infty}K^0_1(x+t)f^-(t)dt,\quad x>0\\
%               &        &     \\
f^-(x)=g^-(x)+\int\limits_{0}^{\infty}K^0_2(x+t)f^+(t)dt+\int\limits_{0}^{\infty}K_2(x-t)f^-(t)dt,\quad x>0

\end{cases}
\end{eqnarray}

\noindent If we define the operators
\begin{eqnarray*}
(\hat{K}_1 f)(x)=\int\limits_{0}^{\infty}K_1(x-t)f(t)dt ,\\
(\hat{K}^0 _1 f)(x)=\int\limits_{0}^{\infty}K_1(x+t)f(t)dt ,\\
(\hat{K}_2 f)(x)=\int\limits_{0}^{\infty}K_2(x-t)f(t)dt ,\\
(\hat{K}^0 _1 f)(x)=\int\limits_{0}^{\infty}K_2(x+t)f(t)dt ,
\end{eqnarray*}
then, the system (\ref{sys2}) will be  changed to the equivalent  operator form
\begin{eqnarray}\label{sys op 1}
\left\lbrace
\begin{array}{lll}
f^+ =g^+ + \hat{K_1}f^+ +\hat{K_1^0}f^-    ,  \\
                     && \\
f^- =g^- + \hat{K}^0_2f^+ +\hat{K_2}f^-    .
\end{array}
\right.
\end{eqnarray}
System (\ref{sys op 1}) is also equivalent to the system
\begin{eqnarray}\label{sys op 2}
\begin{cases}
(\hat{I}-\hat{K_1})f^+ = g^+ + \hat{K^0 _1}f^- ,\\
                    \\
(\hat{I}-\hat{K_2})f^- = g^- + \hat{K^0 _2}f^+ ,
\end{cases}
\end{eqnarray}

where $\hat{I}$ is the identity operator.

\section{Factorization of the convolution equation}
Let us introduce the following classes of operators
\begin{footnotesize}
\begin{eqnarray*}
\Omega =\{\hat{K}:(\hat{K}\varphi)(x)=\int\limits_{0}^{\infty}K(x-t)\varphi(t)dt,\varphi \in L_1(0,\infty),K \in L_1 (\mathbb{R})  \} \phantom{aaaaaaaa}\\
% % % % % % % % % % % % % % % % %
\Omega ^+ =\{\hat{V}^+:(\hat{V}^+\varphi)(x)=\int\limits_{0}^{x}V^+(x-t)\varphi(t)dt,\varphi \in L_1(0,\infty),V^+ \in L_1 (0,\infty)  \}\\
% % % % % % % % % % % % % % % % % % %
\Omega ^- =\{\hat{V}^-:(\hat{V}^-\varphi)(x)=\int\limits_{x}^{\infty}V^-(t-x)\varphi(t)dt,\varphi \in L_1(0,\infty),V^- \in L_1 (0,\infty)  \}\\
% % % % % % % % % % % % % % % % %
\Omega ^0 =\{\hat{K}^0:(\hat{V}^0\varphi)(x)=\int\limits_{0}^{\infty}K^0(x+t)\varphi(t)dt,\varphi \in L_1(0,\infty),K^+ \in L_1 (0,\infty)  \} \phantom{a}.
\end{eqnarray*}
\end{footnotesize}
These operators help us to proof the following statements \cite{m1}
\begin{eqnarray}\label{closness}
\hat{V}^- \hat{K}^0 \in \Omega ^0 ,\quad \hat{K}^0 \hat{V}^+  \in \Omega ^0 ,\quad \hat{V}^- \hat{V}^+ \in \Omega.
\end{eqnarray}
Now we consider the following factorization
\begin{eqnarray}\label{factor1}
(\hat{I}-\hat{K}_j)=(\hat{I}-\hat{V}^-_j)(\hat{I}-\hat{V}^+_j),
\end{eqnarray}

For $j=1,2$ ,   $\quad\hat{K}_j \in \Omega  $  are given and $\hat{V}^-_j \in \Omega^-  $  and $\hat{V}^+_j \in \Omega^+   $ are unknown operators.\\
The factorization (\ref{factor1}) is equivalent to the Yengibarian's system \cite{aren}
\begin{eqnarray}\label{yeng1}
V^\pm (x)=K^\pm (x) +\int\limits_{0}^{\infty} V^\mp _j (t)V^\pm _j (x+t) dt  ,\quad j=1,2.
\end{eqnarray}

The factorization
\begin{eqnarray*}
I-\bar{K}_j(s)=[I-\bar{V}^-_j (s)][I-\bar{V}^+_j (s)] , \quad im(s)=0 ,\quad j=1,2
\end{eqnarray*}
is the symbol of the operators (\ref{factor1}).
In the above formula $\bar{K}_j,\quad \bar{V}^+_j  and \quad    \bar{V}^-_j $ are defined as
\begin{eqnarray*}
\bar{K}_j(s)= \int\limits_{-\infty}^{\infty}K_j(x)e^{ixs}dx  , \quad im(s)=0,\quad j=1,2\\
\bar{V}^+_j(s)= \int\limits_{-\infty}^{\infty}V^+_j(x)e^{ixs}dx  , \quad im(s)\geq 0,\quad j=1,2\\
\bar{V}^-_j(s)= \int\limits_{-\infty}^{\infty}V^-_j(x) e^{ixs}dx  , \quad im(s)\leq 0,\quad j=1,2
\end{eqnarray*}
where $im(s)$ indicates the imaginary part of $s$.\\
If we suppose that the left part of (\ref{factor1}) is invertible,  then the right part of this relation which is contain the Volterra-type operators , will be invertible and their inversion are the renewal-type  and have the following form
\begin{eqnarray}\label{invert1}
(\hat{I}-\hat{V}^\pm)^{-1}= \hat{I}+\hat{\Phi}^\pm  ,\quad \hat{\Phi}^ \pm \in \Omega ^\pm .
\end{eqnarray}
In this relation ${\Phi}^\pm$ are defined as
\begin{eqnarray*}
\Phi^\pm (x)=V^\pm (x) +\int\limits_{0}^{x} V^\pm (x-t)\Phi^\pm  (t) dt  ,\quad x>0 .
\end{eqnarray*}
After using the relations (\ref{sys op 2}) and (\ref{factor1}) then we have
\begin{eqnarray}\label{insert1}
\begin{cases}
(\hat{I}-\hat{V}^-_1)(\hat{I}-\hat{V}^+_1)f^+ = g^+ + \hat{K^0 _1}f^- ,\\
                    \\
(\hat{I}-\hat{V}^-_2)(\hat{I}-\hat{V}^+_2)f^- = g^- + \hat{K^0 _2}f^+  .

\end{cases}
\end{eqnarray}
By considering 
\begin{eqnarray*}
\begin{cases}
F^+ = (\hat{I}-\hat{V}^+_1)f^+, \\
                            \\
F^- = (\hat{I}-\hat{V}^+_2)f^-,
\end{cases}
\end{eqnarray*}
relation  (\ref{insert1}) will become 
\begin{eqnarray}\label{inset2}
\begin{cases}
F^+ = G^+ + \hat{U}^0_1 F^-, \\
                            \\
F^- = G^- + \hat{U}^0_2 F^+,
\end{cases}
\end{eqnarray}
where


\begin{eqnarray}\label{u0}
\begin{cases}
\hat{U}^0_1 =(\hat{I}+\hat{\Phi}^-_1) \hat{K}^0_1(\hat{I}+\hat{\Phi}^-_2),\\
\\
\hat{U}^0_2 =(\hat{I}+\hat{\Phi}^-_2) \hat{K}^0_2(\hat{I}+\hat{\Phi}^-_1),
\end{cases}
\end{eqnarray}
and
\begin{eqnarray}\label{g0}
\begin{cases}
G^+ = (\hat{I}-\hat{\Phi}^-_1)g^+,\\
                            \\
G^- = (\hat{I}-\hat{\Phi}^-_2)g^-.
\end{cases}
\end{eqnarray}
From ( $\ref{closness}$), ($\ref{g0}$) and ($\ref{u0}$) it is easy to verify that
\begin{eqnarray*}
\hat{U}^0_{1,2} \in \Omega^0 \quad and \quad G^\pm \in E^+.
\end{eqnarray*}
The next theorem shows the conditions in which the equation (\ref{inset2}) has a uique solotion .
\begin{theorem}
If the operators $\hat{I}-\hat{K}_j, \quad for\quad j=1,2$ are invertible in $E^+$ then

 	The system (\ref{inset2})which is contain the Hankel –type operators $\hat{U}^0_{1,2} \in \Omega^0$ has the unique solution $(F^+ ,F^-) \in E^+ \times E^+ .$
 	In this case, $f^+$ and $f^-$  can be found by the following system
\begin{eqnarray*}
\begin{cases}
f^+=(\hat{I}+ \hat{\Phi}^+_1)F^+\\
\\
f^-=(\hat{I}+ \hat{\Phi}^+_2)F^-
\end{cases}
\end{eqnarray*}

\end{theorem}
proof: See \cite{aren}.
\section{Approximating the solution of convolution equation with two kernels}
Numerical approximating of the integral equation of convolution type has worked by a lot of authors ( \cite{bus}, \cite{chan} and \cite{enmel} ).In \cite{chan}, Chandrasekhar introduced the Discrete Ordinate Method (DOM) .\\
N.B.Yengibaryan(Engibaryan) and E.A.Melkonyan introduced the method for numerical approximating \cite{enmel},in this method the kernel where is the super position of exponential  approximate by following finite linear combination of exponentials
\begin{eqnarray*}
K(x)\simeq \tilde{K}(x)=\sum\limits_{m=0}^{N}c_m exp(-s_m x)  , \quad 0\leq K(x)\leq \tilde{K}(x) ,
\end{eqnarray*}
where $s_k \in (a,b)\quad for \quad k=0,1,2,\cdots ,N .$\\

Pressdorf and et.al., introduced the discrete Wiener-Hopf equations \cite{press, gofel},  our approach is based on their works.\\
I changed the integral equation with two kernels (\ref{eq:equation}) to the dual system of of integral equations (\ref{sys2}) and showed that this system and hence (\ref{eq:equation}) has answer and now i want to approximate the dual system (\ref{sys2}) and by finding its answers, the answers of (\ref{eq:equation}) can be approximate. 

{\bf remark}: 
Let us remind that a Toeplitz matrix is an $n\times n$  matrix $T_n$ in the form of 
\begin{eqnarray*}
 T_n=
 \begin{bmatrix}
 t_{0} & t_{-1} & t_{-2} &  \cdots  &   t_{-(n-1)} \\
 t_{1} & t_{0}  & t_{-1} &  \cdots  &   t_{-(n-2)} \\
 t_{2} & t_{1}  & t_{0}   & \cdot   &   t_{-(n-3)} \\
 \vdots & \vdots & \vdots  & \ddots  &   \vdots             \\
 t_{n-1} & t_{n-2} & t_{n-3} & \cdots &   t_{0}
 \end{bmatrix},
\end{eqnarray*}
where $t_{k,j}=t_ {k-j}\quad for\quad k,j = 0,1,2,\cdots ,n-1$, Similarly, a Hankel matrix is an $n\times n$  matrix $H_n$ in the form of 
\begin{eqnarray*}
 H_n=
 \begin{bmatrix}
 h_{0} & h_{1} & h_{2} &  \cdots  &   h_{(n-1)} \\
 h_{1} & h_{2}  & h_{3} &  \cdots  &   h_{n} \\
 h_{2} & h_{3}  & h_{4}   & \cdot   &   t_{(n+3)} \\
 \vdots & \vdots & \vdots  & \ddots  &   \vdots             \\
 h_{n-1} & h_{n} & h_{n+1} & \cdots &   h_{2n-2}
 \end{bmatrix},
\end{eqnarray*}
where $h_{k,j}=h_{k+j}\quad for\quad k,j=k,j = 0,1,2,\cdots ,n-1 $.\\ 
We know that there are also the infinite Hankel and Toeplitz matrices of the same figure.\\
Now let us introduce the Dual algebraic system
\begin{eqnarray}\label{algebraic sys1}
\begin{cases}
f^+_j =g^+_j + \sum\limits_{i=1}^{\infty} a_{j+i} f^-_i + \sum\limits_{i=0}^{\infty} a_{j-i} f^+_i \quad , \quad j=0,1,2,\cdots\\
\\
f^-_j =g^-_j + \sum\limits_{i=1}^{\infty} b_{-(j+i)} f^+_i + \sum\limits_{i=0}^{\infty} b_{-(j-i)} f^-_i \quad , \quad j=1,2,\cdots


\end{cases}
\end{eqnarray}

which is correspond to the dual system of integral equations (\ref{sys1}).\\
The same as the integral operators in section (2), here also consider the following matrix operators

\begin{eqnarray*}
Kf=\left( \sum\limits_{0}^{\infty} a_{1-i}f_i , \sum\limits_{0}^{\infty} a_{2-i} f_i , \sum\limits_{0}^{\infty} a_{3-i} f_i , \cdots \right)^T\\
  % % % % % % % % % % % % % % % % % %                 \\
K^0 f = \sum\limits_{i=1}^{\infty} a_{j+i}f_i \quad , \quad j=0,1,2,\cdots\\
% % % % % % % % % % % % % % %\\
H f = \sum\limits_{i=0}^{\infty} b_{j-i}f_i \quad , \quad j=0,1,2,\cdots\\
% % % % % % % % % % % % % % % % %\\
H^0 f = \sum\limits_{i=1}^{\infty} b_{j+i}f_i \quad , \quad j=0,1,2,\cdots\\
\end{eqnarray*}
By the above operators, one can change the system  (\ref{algebraic sys1}) to the following form
\begin{eqnarray}\label{alg op sys1}
\begin{cases}
f^+ = g^+ + Kf^+ + K^0 f^-\\
\\
f^- = g^- + Hf^- + H^0 f^+.
\end{cases}
\end{eqnarray}
We can  rewrite (\ref{alg op sys1}) as
\begin{eqnarray}\label{alg op sys 2}
\begin{cases}
(I-K)f^+ = g^+ + K^0 f^-,\\
 \\
(I-H)f^- = g^- + H^0 f^+.
\end{cases}
\end{eqnarray}

In the previous relation, $I$ is the  identity matrix operator.\\
Suppose that the following factorization exists
\begin{eqnarray}\label{alg fac}
\begin{cases}


I-K=(I-K^-)(I-K^+),\\
\\
I-H=(I-H^-)(I-H^+).
\end{cases}
\end{eqnarray}
Let us suppose that the matrices $(I-K^\pm)$   and $(I-H^\pm)$ are invertible and their inversions are in the forms
\begin{eqnarray}\label{alg inv op}
\begin{cases}
(I-K^\pm)^{-1} =I+ \Phi^{\pm},\\
\\
(I-H^\pm)^{-1} =I+ \Psi ^{\pm}.
\end{cases}
\end{eqnarray}
From relations (\ref{alg op sys 2}) and (\ref{alg fac})  we have

\begin{eqnarray}\label{alg sys fac2}
\begin{cases}
(I-K^-)(I-K^+)f^+ =g^+ + K^0 f^-,\\
\\
(I-H^-)(I-H^+)f^- =g^- + H^0 f^+.
\end{cases}
\end{eqnarray}
Now we define the following vectors
\begin{eqnarray}\label{vec}
\begin{cases}
\omega^+ =(I-K^+)f^+,\\
\\
\omega^- =(I-H^+)f^-.
\end{cases}
\end{eqnarray}
From equations (\ref{alg inv op}) and (\ref{vec}) one can write
\begin{eqnarray}\label{vec 2}
\begin{cases}
f^+ = (I+ \Phi ^+) \omega ^+,\\
\\
f^- = (I+ \Psi ^+) \omega ^-.
\end{cases}
\end{eqnarray}
From systems (\ref{alg sys fac2}), (\ref{vec}) and (\ref{vec 2}) we can obtain the following system of algebraic equations
\begin{eqnarray} \label{28}
\begin{cases}
(I-K^-)\omega ^+ =g^+ + K^0 (I+ \Psi ^+) \omega ^-,\\
\\
(I-H^-)\omega ^- =g^- + H^0 (I+ \Phi ^+) \omega ^+.
\end{cases}
\end{eqnarray}
Multiplying both sides of the first equation in (\ref{28}) by  $ (I-K^-)^{-1} $ and both sides of the second equation  by
 $ (I-H^-)^{-1} $, then we can receive to the following system
\begin{eqnarray}\label{29}
\begin{cases}
\omega ^+ =(I+ \Phi^-)g^+ +(I+ \Phi^-) K^0 (I+ \Psi ^+) \omega ^-,\\
\\
\omega ^- =(I + \Psi ^-)g^- + (I + \Psi ^-)H^0 (I+ \Phi ^+) \omega ^+.
\end{cases}
\end{eqnarray}
Now we introduce the following vectors
\begin{eqnarray*}
(I+ \Phi^-)g^+ =G^+,\\
(I+ \Psi^-)g^- =G^-,\\
(I+ \Phi^-)K^0 (I+ \Psi ^+) =U^0_1,\\
(I+ \Psi^-)H^0 (I+ \Phi ^+) =U^0_2.
\end{eqnarray*}
These four vectors help us to write the system (\ref{29}) as
\begin{eqnarray}\label{omega}
\begin{cases}
\omega ^+ =G^+ +U^0_1 \omega ^-,\\
\\
\omega ^- =G^- +U^0_2 \omega ^+.
\end{cases}
\end{eqnarray}

If we take into account the properties of the classes $ \Omega, \Omega^\pm $ and $ \Omega^0 $, then we can see that
\begin{eqnarray}
U^0_{1,2}\in \Omega^0, \quad G^\pm \in E^+.
\end{eqnarray}
The factorization of matrix operators (\ref{alg fac})  are equivalent to the corresponding nonlinear systems
\begin{eqnarray}\label{32}
\begin{cases}
K^+_i =a_i + \sum\limits_{j=0}^{\infty}K^-_j K^+_{i+j}, \quad i=0,1,2,\cdots\\
\\
K^-_i =a_{-i} + \sum\limits_{j=0}^{\infty}K^-_{i+j} K^+_{j}, \quad i=0,1,2,\cdots .\\

\end{cases}
\end{eqnarray}

Finally, the factorization of matrix operators (\ref{alg fac}) reduce the solution of system (\ref{algebraic sys1}) to the solution of the following  systems of equations with triangular matrices\\

\begin{eqnarray}\label{final1}
\begin{cases}
\rho^+_i - \sum\limits_{j=i}^{\infty}K^-_{j-i}\rho^+_j =\eta^+_i + (K^0 f^-)_i, \quad i=0,1,2,\cdots \\
\\
f^+_i - \sum\limits_{j=0}^{i}K^-_{i-j} f^-_j =\rho^+_i, \phantom{aaaaaaaaa} \quad i=0,1,2,\cdots \\
\end{cases}
\end{eqnarray}
and
\begin{eqnarray}\label{final2}
\begin{cases}
\theta^+_i - \sum\limits_{j=i}^{\infty}H^-_{j-i}\theta^+_j =\eta^-_i + (H^0 f^+)_i, \quad i=0,1,2,\cdots \\
\\
f^-_i - \sum\limits_{j=0}^{i}H^+_{i-j} f^-_j =\theta^+_i, \phantom{aaaaaaaaaa}  i=0,1,2,\cdots \\
\end{cases}
\end{eqnarray}
Here we propose the following theorem.
\begin{theorem}
The dual system (\ref{algebraic sys1}) can be solved by the following scheme:
\begin{enumerate}
\item We solve (\ref{32}) using successive iterative method.\\
(For more exploration about successive iterative method one can refer to "Integral Equation" books ) 
\item From (\ref{final1}) and (\ref{final2}) we can compute $K^\pm$  and $H^\pm$. It makes it possible to also find the $\omega^+$  and $\omega^-$ from (\ref{omega})\\
\item  $f^+$ and $f^-$  can be obtained from (\ref{vec 2}).\\
\item Dual integral equation (\ref{sys2}) can be approximated from last step.\\
\item solution of equation (\ref{eq:equation}) can be approximated.
\end{enumerate}
\end{theorem}

\section{Conclusions}
We introduced and studied a new integral equation of convolution type with two kernels, and after some manipulations we showed that it is solvable. In the latest section we introduced a new way for approximating of this kind of equations.
%%%%%%%%%%%%%%%%%%%%%
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%\section{Acknowledgment}
%The author expresses his gratitude to Dr. A. Rafiei for useful discussions.

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{\small

\noindent{\bf Massoud Mashreghi}

\noindent Department of Mathematics

\noindent Assistant Professor of Mathematics

\noindent Hakim Sabzevari University

\noindent Sabzevar, Iran

\noindent E-mail: massoud.mashreghi@gmail.com}\\


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